Re: The Riddler's House of Riddles
Nope, it uses that as an example...
~Wornstrum~
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Nope, it uses that as an example...
hrm
or they could just leave the blind guy last and he crosses without anybody bringing the flashlight back.
1+2- 2 mins
1 min to go back with flashlight
5+10- 10 mins
2 min guy go back with flashlight
1+2 = 2mins
total = 17 mins.
3 trips 2 return trips..
1 min and 2 min guy go over
1 min guy goes back
5 and 10 min guy go over
2 min guy goes back
1 and 2 min guy go over
= 17 mins altogether ![]()
damnit just noticed i am nothing got it before me ![]()
Three friends check into a motel for the night and the clerk tells them the bill is $30, payable in advance. So, they each pay the clerk $10 and go to their room. A few minutes later, the clerk realizes he has made an error and overcharged the trio by $5. He asks the bellhop to return $5 to the 3 friends who had just checked in. The bellhop sees this as an opportunity to make $2 as he reasons that the three friends would have a tough time dividing $5 evenly among them; so he decides to tell them that the clerk made a mistake of only $3, giving a dollar back to each of the friends. He pockets the leftover $2 and goes home for the day! Now, each of the three friends gets a dollar back, thus they each paid $9 for the room which is a total of $27 for the night. We know the bellhop pocketed $2 and adding that to the $27, you get $29, not $30 which was originally spent. Where did the other dollar go????
seen this one before so taking myself out this time
This is something my friend asked me at work the other week and it took me ages to work it out - infact i never did..
but i think its actually a math fail..
In the sense that: you cant switch between counting down and counting up (10 to 9) (27 to 29)
When you count down you count down to 0.. Thus
29-1
28-2
27-3
26-4..
etc till
20-10
10-20
0-30
theres your thirty ![]()
Humidity +1
Answer:
The facts in this riddle are clear: There is an initial $30 charge. It should have been $25, so $5 must be returned and accounted for. $3 is given to the 3 friends, $2 is kept by the bellhop - there you have the $5. The trick to this riddle is that the addition and subtraction are done at the wrong times to misdirect your thinking - and quite successfully for most. Each of the 3 friends did indeed pay $9, not $10, and as far as the friends are concerned, they paid $27 for the night. But we know that the clerk will tell us that they were charged only $25 and when you add the $3 returned with the $2 kept by the bellhop, you come up with $30.
Take The Letters D I S
Add One More Letter
They in fact paid $28 for the hotel rooms ($30-$5=25 and they had a total of $3 returned which means they paid a total of $28 for the rooms)
DESI
man another one i have seen before. this will be good. im sorry but whoever gets this one has either seen it before or is cheating lol.
pfft no fair, my english isn't good enough for wordgames, next! ![]()
Take The Letters D I S
Add One More Letter
Modestus Experitus
Arby: A very strict mod, reminds me of a fat redneck who drives a truck around all day with a beer in one hand. I hated this guy at the start, however, I played a round in PW with him where he went as an anonymous player. Our fam got smashed up and everyone pretty much left. Arby stayed around and helped out the remaining family. At the end of the round he revealed himself.... My views on him have changed since. Your a good guy.....
0 points awarded (1st time)
Answer: The letter you add is
A jail consists of 100 cells in a line, all starting out closed. The warden gets drunk one night and goes along opening every single cell. He then returns to the beginning, and "toggles" every second cell -- in this case, they're all open, so he closes every other cell door. He then runs to the beginning again, and "toggles" every third cell, then again with every fourth cell, and so on until the very last run in which he only toggles the hundredth cell, then drops down from exhaustion.
How many cells are left open after this process?
2
1
4
9
9 - all square numbers ![]()
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